.5x^2+110x+300=300

Solution for .5x^2+110x+300=300 equation:

.5x^2+110x+300=300

We move all terms to the left:

.5x^2+110x+300-(300)=0

We add all the numbers together, and all the variables

.5x^2+110x=0

a = .5; b = 110; c = 0;
Δ = b2-4ac
Δ = 1102-4·.5·0
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-110}{2*.5}=\frac{-220}{1}
=-220
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+110}{2*.5}=\frac{0}{1}
=0
$